69 lines
2 KiB
Ruby
69 lines
2 KiB
Ruby
# frozen_string_literal: true
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module Rpl
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module Lang
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module Core
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module_function
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# convert an object into a string
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def to_string( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [:any] )
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stack << { type: :string,
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value: args[0][:value].to_s }
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end
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# convert a string into an object
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def from_string( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[string]] )
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parsed_input = Rpl::Lang::Parser.new.parse_input( args[0][:value] )
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stack + parsed_input
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end
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# convert ASCII character code in stack level 1 into a string
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def chr( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[numeric]] )
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stack << { type: :string,
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value: args[0][:value].chr }
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end
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# return ASCII code of the first character of the string in stack level 1 as a real number
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def num( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[string]] )
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stack << { type: :numeric,
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base: 10,
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value: args[0][:value].ord }
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end
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# return the length of the string
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def size( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[string]] )
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stack << { type: :numeric,
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base: 10,
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value: args[0][:value].length }
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end
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# search for the string in level 1 within the string in level 2
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def pos( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[string], %i[string]] )
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stack << { type: :numeric,
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base: 10,
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value: args[1][:value].index( args[0][:value] ) }
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end
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# return a substring of the string in level 3
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def sub( stack )
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stack, args = Rpl::Lang::Core.stack_extract( stack, [%i[numeric], %i[numeric], %i[string]] )
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stack << { type: :string,
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value: args[2][:value][args[1][:value]..args[0][:value]] }
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end
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end
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end
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end
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