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tms34020: Fix BLMOVE aligment handling
BLMOVE has actually 4 different cases of execution based on two lowest bits in opcode, which were not properly handled. Fixes endless loop in atronic / atricmon.
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1 changed files with 27 additions and 34 deletions
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@ -2050,9 +2050,14 @@ void tms340x0_device::blmove(uint16_t op)
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if (!m_is_34020) { unimpl(op); return; }
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/* src and dst are aligned */
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if (!(src & 0x0f) && !(dst & 0x0f))
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{
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bool S = op & (1 << 1);
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bool D = op & (1 << 0);
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if ((S == false && (src & 0xf)) || (D == false && (dst & 0xf))) {
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logerror("020:BLMOVE alignment error: PC=%x: S=%d, D=%d, src=%x, dst=%x, bits=%d\n", m_pc, S, D, src, dst, bits);
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}
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// logerror("020:BLMOVE: PC=%x: S=%d, D=%d, src=%x, dst=%x, bits=%d\n", m_pc, S, D, src, dst, bits);
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while (bits >= 16 && m_icount > 0)
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{
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TMS34010_WRMEM_WORD(dst, TMS34010_RDMEM_WORD(src));
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@ -2069,31 +2074,19 @@ void tms340x0_device::blmove(uint16_t op)
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bits = 0;
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m_icount -= 2;
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}
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}
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/* src is aligned, dst is not */
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else if (!(src & 0x0f))
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{
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logerror("020:BLMOVE with aligned src and unaligned dst\n");
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}
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/*
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TODO: We do not currently emulate precisely how B0 and B2 are modified during the operation:
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if D == 0, then B0 and B2 remain fixed during execution and are only incremented after operation completes.
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if D == 1, then B2 is incremented during move, B0 remains fixed until operation completes.
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*/
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/* dst is aligned, src is not */
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else if (!(dst & 0x0f))
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{
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logerror("020:BLMOVE with unaligned src and aligned dst\n");
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}
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/* neither are aligned */
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else
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{
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logerror("020:BLMOVE with completely unaligned src and dst\n");
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}
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/* update the final results */
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BREG(0) = src;
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BREG(2) = dst;
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BREG(7) = bits;
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// logerror("020:BLMOVE: PC=%x: finished: B0=%x, B2=%x, B7=%d\n", m_pc, src, dst, bits);
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/* if we're not done yet, back up the PC */
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if (bits != 0)
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m_pc -= 0x10;
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