Merge pull request #161 from jsca-kwok/jk-isomorphic-strings

Isomorphic Strings Algorithm
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Vitor Oliveira 2021-07-20 19:32:19 -07:00 committed by GitHub
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* [Common Characters](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/common_characters.rb)
* [Find All Duplicates In An Array](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/find_all_duplicates_in_an_array.rb)
* [Good Pairs](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/good_pairs.rb)
* [Isomorphic Strings](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/isomorphic_strings.rb)
* [Richest Customer Wealth](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/richest_customer_wealth.rb)
* [Two Sum](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/two_sum.rb)
* [Uncommon Words](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/uncommon_words.rb)

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# Challenge name: Isomorphic Strings
#
# Given two strings s and t, determine if they are isomorphic.
# Two strings s and t are isomorphic if the characters in s can be replaced to get t.
# All occurrences of a character must be replaced with another character while preserving the order of characters.
# No two characters may map to the same character, but a character may map to itself.
#
# Example 1:
# Input: s = "egg", t = "add"
# Output: true
#
# Example 2:
# Input: s = "foo", t = "bar"
# Output: false
#
# Example 3:
# Input: s = "paper", t = "title"
# Output: true
#
# Constraints:
# 1 <= s.length <= 5 * 104
# t.length == s.length
# s and t consist of any valid ascii character.
# Approach 1: Hash Map
# Time Complexity: O(N)
# Space Complexity: O(N)
def isomorphic_strings_check(s, t)
# store character mappings
map = {}
# store already mapped characters
set = []
(0..s.length - 1).each do |i|
# store characters to compare
char1 = s[i]
char2 = t[i]
# if char1 is mapped
if map[char1]
# return false if char1 is mapped to a different character than already present
return false if map[char1] != char2
# if char1 is not mapped
else
# return false if char2 is already mapped to a different character
return false if set.include?(char2)
# checks passed: add new character map and track that char2 has been mapped
map[char1] = char2
set << char2
end
end
return true
end
puts isomorphic_strings_check("egg", "add")
# => true
puts isomorphic_strings_check("foo", "bar")
# => false
puts isomorphic_strings_check("paper", "title")
# => true