Add brute force solution

data_structures/arrays/get_products_of_all_other_elements.rb

@@ -0,0 +1,23 @@
+# Arrays - Get Products of all other elements in Ruby
+
+# Algorithm challenge description:
+# Given an array of integers, return a new array such that
+# each element at index `i` of the new array is the product of
+# all the numbers in the original array except the one at `i`.
+
+# 1. Brute force solution
+def calculate_products_of_all_other_elements(nums)
+  products_other_elements = Array.new(nums.length, 1)
+
+  nums.each_with_index do |num1, i|
+    nums.each_with_index do |num2, j|
+      if (i != j)
+        products_other_elements[i] = products_other_elements[i] * num2
+      end
+    end
+  end
+
+  products_other_elements
+end
+
+puts(calculate_products_of_all_other_elements([1, 2, 3]))