Add hash table approach

data_structures/arrays/arrays_intersection.rb

@@ -0,0 +1,55 @@
+# Given three integer arrays arr1, arr2 and arr3 sorted in strictly increasing order, return a sorted array of only the integers that appeared in all three arrays.
+#
+# Example 1:
+#
+# Input: arr1 = [1,2,3,4,5], arr2 = [1,2,5,7,9], arr3 = [1,3,4,5,8]
+# Output: [1,5]
+# Explanation: Only 1 and 5 appeared in the three arrays.
+#
+# Example 2:
+#
+# Input: arr1 = [197,418,523,876,1356], arr2 = [501,880,1593,1710,1870], arr3 = [521,682,1337,1395,1764]
+# Output: []
+#
+#
+
+#
+# Approach: Hash table
+#
+
+# Complexity Analysis
+
+# Time Complexity: O(n) - n is the total length of
+# all of the input arrays.
+# Space Complexity: O(n) - n is the total length of all of the
+# input arrays. This is because we adopted a Hash table to store all
+# numbers and their number of appearances as values.
+
+def arrays_intersection(arr1, arr2, arr3)
+  hash = Hash.new(0)
+
+  add_to_hash(arr1, hash)
+  add_to_hash(arr2, hash)
+  add_to_hash(arr3, hash)
+
+  hash.select { |key, value| value == 3 }.keys
+end
+
+def add_to_hash(arr, hash)
+  arr.each_with_index do |value, index|
+   hash[value] += 1
+  end
+end
+
+arr1 = [1,2,3,4,5]
+arr2 = [1,2,5,7,9]
+arr3 = [1,3,4,5,8]
+print arrays_intersection(arr1, arr2, arr3)
+# Output: [1,5]
+# Explanation: Only 1 and 5 appeared in the three arrays.
+
+arr1 = [197,418,523,876,1356]
+arr2 = [501,880,1593,1710,1870]
+arr3 = [521,682,1337,1395,1764]
+print arrays_intersection(arr1, arr2, arr3)
+# Output: []