Merge branch 'master' into jk-shuffle-array

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Vitor Oliveira 2021-03-29 14:34:55 -07:00 committed by GitHub
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* [Find The Highest Altitude](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/find_the_highest_altitude.rb)
* [Fizz Buzz](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/fizz_buzz.rb)
* [Get Products Of All Other Elements](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/get_products_of_all_other_elements.rb)
* [Jewels And Stones](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/jewels_and_stones.rb)
* [Remove Elements](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/remove_elements.rb)
* [Shuffle Array](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/shuffle_array.rb)
* [Richest Customer Wealth](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/richest_customer_wealth.rb)
* [Single Number](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/single_number.rb)
* [Shuffle Array](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/shuffle_array.rb)
* [Sort Squares Of An Array](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/sort_squares_of_an_array.rb)
* [Two Sum](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/two_sum.rb)
* [Two Sum Ii](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/arrays/two_sum_ii.rb)
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* [Invert](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/binary_trees/invert.rb)
* [Postorder Traversal](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/binary_trees/postorder_traversal.rb)
* [Preorder Traversal](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/binary_trees/preorder_traversal.rb)
* Hash Table
* [Richest Customer Wealth](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/hash_table/richest_customer_wealth.rb)
* Linked Lists
* [Circular Linked List](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/linked_lists/circular_linked_list.rb)
* [Doubly Linked List](https://github.com/TheAlgorithms/Ruby/blob/master/data_structures/linked_lists/doubly_linked_list.rb)
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* [Fibonacci](https://github.com/TheAlgorithms/Ruby/blob/master/maths/fibonacci.rb)
* [Number Of Digits](https://github.com/TheAlgorithms/Ruby/blob/master/maths/number_of_digits.rb)
* [Power Of Two](https://github.com/TheAlgorithms/Ruby/blob/master/maths/power_of_two.rb)
* [Prime Number](https://github.com/TheAlgorithms/Ruby/blob/master/maths/prime_number.rb)
* [Square Root](https://github.com/TheAlgorithms/Ruby/blob/master/maths/square_root.rb)
* [Square Root Test](https://github.com/TheAlgorithms/Ruby/blob/master/maths/square_root_test.rb)
* [Sum Of Digits](https://github.com/TheAlgorithms/Ruby/blob/master/maths/sum_of_digits.rb)

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# Challenge name: Jewels and Stones
#
# You're given strings jewels representing the types of stones that are jewels,
# and stones representing the stones you have. Each character in stones is a type
# of stone you have. You want to know how many of the stones you have are also
# jewels.
#
# Letters are case sensitive, so "a" is considered a different type of stone from "A".
#
# Example 1:
#
# Input: jewels = "aA", stones = "aAAbbbb"
# Output: 3
#
# Example 2:
#
# Input: jewels = "z", stones = "ZZ"
# Output: 0
#
#
# Constraints:
#
# 1 <= jewels.length, stones.length <= 50
# jewels and stones consist of only English letters.
# All the characters of jewels are unique.
#
# Approach 1: Brute Force
#
# Time Complexity: O(n^2)
#
def find_jewels(jewels, stones)
jewels_array = jewels.split('')
stones_array = stones.split('')
result = 0
jewels_array.each do |jewel|
stones_array.each do |stone|
if jewel == stone
result += 1
end
end
end
result
end
puts find_jewels("aA", "aAAbbbb")
# => 3
puts find_jewels("z", "ZZ")
# => 0
#
# Approach 2: Hash
#
# Time Complexity: O(n)
#
def find_jewels(jewels, stones)
jewels_array = jewels.split('')
stones_array = stones.split('')
result_hash = {}
result = 0
stones_array.each do |stone|
if result_hash[stone]
result_hash[stone] += 1
else
result_hash[stone] = 1
end
end
jewels_array.each do |jewel|
if result_hash[jewel]
result += result_hash[jewel]
else
result
end
end
result
end
puts find_jewels("aA", "aAAbbbb")
# => 3
puts find_jewels("z", "ZZ")
# => 0

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# Challenge name: Richest Customer Wealth
#
# You are given an m x n integer grid accounts where accounts[i][j]
# is the amount of money the ith customer has in the jth bank.
#
# Return the wealth that the richest customer has.
# A customer's wealth is the amount of money they have in all
# their bank accounts. The richest customer is the customer that
# has the maximum wealth.
#
# Example 1:
# Input: accounts = [[1,2,3],[3,2,1]]
# Output: 6
# Explanation:
# 1st customer has wealth = 1 + 2 + 3 = 6
# 2nd customer has wealth = 3 + 2 + 1 = 6
# Both customers are considered the richest with a wealth of 6
# each, so return 6.
#
# Example 2:
# Input: accounts = [[1,5],[7,3],[3,5]]
# Output: 10
# Explanation:
# 1st customer has wealth = 6
# 2nd customer has wealth = 10
# 3rd customer has wealth = 8
# The 2nd customer is the richest with a wealth of 10.
#
# Example 3:
# Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
# Output: 17
#
# Approach: Brute Force
#
# Time Complexity: O(n)
#
def find_richest_customer_wealth(accounts)
summed_accounts = []
accounts.each do |customer|
summed = 0
customer.each do |account|
summed += account
end
summed_accounts.push(summed)
end
summed_accounts.sort.pop()
end
puts find_richest_customer_wealth([[1,2,3],[3,2,1]])
# => 6
puts find_richest_customer_wealth([[1,5],[7,3],[3,5]])
# => 10
puts find_richest_customer_wealth([[2,8,7],[7,1,3],[1,9,5]])
# => 17

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# Challenge name: Richest Customer Wealth
#
# You are given an m x n integer grid accounts where accounts[i][j]
# is the amount of money the ith customer has in the jth bank.
#
# Return the wealth that the richest customer has.
# A customer's wealth is the amount of money they have in all
# their bank accounts. The richest customer is the customer that
# has the maximum wealth.
#
# Example 1:
# Input: accounts = [[1,2,3],[3,2,1]]
# Output: 6
# Explanation:
# 1st customer has wealth = 1 + 2 + 3 = 6
# 2nd customer has wealth = 3 + 2 + 1 = 6
# Both customers are considered the richest with a wealth of 6
# each, so return 6.
#
# Example 2:
# Input: accounts = [[1,5],[7,3],[3,5]]
# Output: 10
# Explanation:
# 1st customer has wealth = 6
# 2nd customer has wealth = 10
# 3rd customer has wealth = 8
# The 2nd customer is the richest with a wealth of 10.
#
# Example 3:
# Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
# Output: 17
#
# Approach: Hash
#
# Time Complexity: O(n)
#
def find_richest_customer_wealth(accounts)
result_hash = {}
accounts.each_with_index do |customer, i|
result_hash[i] = customer.sum
end
highest_value = 0
result_hash.each do |k, v|
if v > highest_value
highest_value = v
end
end
highest_value
end
puts find_richest_customer_wealth([[1,2,3],[3,2,1]])
# => 6
puts find_richest_customer_wealth([[1,5],[7,3],[3,5]])
# => 10
puts find_richest_customer_wealth([[2,8,7],[7,1,3],[1,9,5]])
# => 17

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maths/prime_number.rb Normal file
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# A ruby program to check a given number is prime or not
# Mathematical explanation: A number which has only 2 factors i.e., 1 (one) and itself
# Prime number check function
def prime_number(number)
if number <= 1
non_prime_flag = true
elsif number == 2
non_prime_flag = false
elsif number % 2 == 0
non_prime_flag = true
else
non_prime_flag = (2..Math.sqrt(number)).any? { |i| number % i == 0 }
end
if !non_prime_flag
puts "The given number #{number} is a Prime."
else
puts "The given number #{number} is not a Prime."
end
end
# Non-prime input
prime_number(1)
# prime input
# Number 2 is an even prime number
prime_number(2)
# Non-prime input
prime_number(20)
# Negative input
prime_number(-21)