remove duplication

data_structures/hash_table/anagram_checker.rb

@@ -17,6 +17,7 @@
 #
 # Approach: Hash table
 #
+
 # Complexity analysis:
 #
 # Time complexity: O(n). Time complexity is O(n) since accessing the counter
@@ -59,42 +60,6 @@ t = 'ab'
 puts(is_anagram(s, t))
 # => false
 
-
-def is_anagram(s, t)
-  s_length = s.length
-  t_length = t.length
-  counter = Hash.new(0)
-
-  return false unless s_length == t_length
-
-  (0...s_length).each do |i|
-    counter[s[i]] += 1
-  end
-
-  (0...s_length).each do |i|
-    counter[t[i]] -= 1
-
-    return false if counter[t[i]] < 0
-  end
-
-  true
-end
-
-s = 'anagram'
-t = 'nagaram'
-puts(is_anagram(s, t))
-# => true
-
-s = 'rat'
-t = 'car'
-puts(is_anagram(s, t))
-# => false
-
-s = 'a'
-t = 'ab'
-puts(is_anagram(s, t))
-# => false
-
 #
 # Approach 2: Hash table
 #