2019-10-21 19:39:15 +02:00
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# Works only on sorted arrays.
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# Finding element by creating step in array and jump ahead by fixed steps and finding element using linear search inside that steped array.
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# Time Complexity : O(√n)
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2021-02-07 07:48:35 +01:00
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def jump_search(arr, x)
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2019-10-21 19:39:15 +02:00
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n = arr.length;
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# Finding block size to be jumped
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step = Math.sqrt(n);
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prev = 0;
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# Finding the block where element is
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# present (if it is present)
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while (arr[[step, n].min - 1] < x) do
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prev = step;
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step += Math.sqrt(n);
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if (prev >= n)
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return -1;
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end
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end
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# Doing a linear search for x in block
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# beginning with prev.
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while (arr[prev] < x) do
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prev = prev + 1;
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# If we reached next block or end of
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# array, element is not present.
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if (prev == [step, n].min)
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return -1;
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end
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end
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# If element is found
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if (arr[prev] == x)
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return prev;
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end
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return -1;
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end
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puts "Enter a sorted space-separated list:"
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arr = gets.chomp.split(' ').map(&:to_i)
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puts "Enter the value to be searched:"
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value = gets.chomp.to_i
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2021-02-07 07:48:31 +01:00
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index = jump_search(arr, value)
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2019-10-21 19:39:15 +02:00
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puts index == -1 ? "Element not found" : "Number #{value} is at #{index}"
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