TheAlgorithms-Ruby/data_structures/arrays/richest_customer_wealth.rb

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# Challenge name: Richest Customer Wealth
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#
# You are given an m x n integer grid accounts where accounts[i][j]
# is the amount of money the ith customer has in the jth bank.
#
# Return the wealth that the richest customer has.
# A customer's wealth is the amount of money they have in all
# their bank accounts. The richest customer is the customer that
# has the maximum wealth.
#
# Example 1:
# Input: accounts = [[1,2,3],[3,2,1]]
# Output: 6
# Explanation:
# 1st customer has wealth = 1 + 2 + 3 = 6
# 2nd customer has wealth = 3 + 2 + 1 = 6
# Both customers are considered the richest with a wealth of 6
# each, so return 6.
#
# Example 2:
# Input: accounts = [[1,5],[7,3],[3,5]]
# Output: 10
# Explanation:
# 1st customer has wealth = 6
# 2nd customer has wealth = 10
# 3rd customer has wealth = 8
# The 2nd customer is the richest with a wealth of 10.
#
# Example 3:
# Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
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# Output: 17
#
# Approach 1: Brute Force
#
# Time Complexity: O(n)
#
def find_richest_customer_wealth(accounts)
summed_accounts = []
accounts.each do |customer|
summed = 0
customer.each do |account|
summed += account
end
summed_accounts.push(summed)
end
summed_accounts.sort.pop()
end
puts find_richest_customer_wealth([[1,2,3],[3,2,1]])
# => 6
puts find_richest_customer_wealth([[1,5],[7,3],[3,5]])
# => 10
puts find_richest_customer_wealth([[2,8,7],[7,1,3],[1,9,5]])
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# => 17
#
# Approach 2: Hash
#
# Time Complexity: O(n)
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#
def find_richest_customer_wealth(accounts)
result_hash = {}
accounts.each_with_index do |customer, i|
result_hash[i] = customer.sum
end
highest_value = 0
result_hash.each do |k, v|
if v > highest_value
highest_value = v
end
end
highest_value
end
puts find_richest_customer_wealth([[1,2,3],[3,2,1]])
# => 6
puts find_richest_customer_wealth([[1,5],[7,3],[3,5]])
# => 10
puts find_richest_customer_wealth([[2,8,7],[7,1,3],[1,9,5]])
# => 17